Electrolysis of Water — the 2:1 rule

Electric current splits water into hydrogen and oxygen — and hydrogen always collects at twice the volume of oxygen.

H₂ (cathode) O₂ (anode) H⁺ cation SO₄²⁻ anion e⁻
ELECTROLYSING
Current I2.0 A
Charge Q0 C
n(H₂)0 mol
V(H₂)0.0 mL
V(O₂)0.0 mL
time t0.0 s
F96485 C/mol
Q = I·t (charge passed) → 0.0 C  ·  n(H₂) = Q/(z·F) = 0.0/(2×96485) = 0 mol  ·  V(H₂):V(O₂) = 0.0 : 0.0 = 2.00 : 1.00

Concept — splitting water, and the 2:1 rule

Direct current through acidified water (dilute H₂SO₄, added so the water conducts) splits it: 2 H₂O → 2 H₂ + O₂. Reduction happens at the cathode (−), where hydrogen bubbles off; oxidation happens at the anode (+), where oxygen bubbles off. Because freeing one O₂ molecule needs four electrons but each H₂ needs only two, twice as many H₂ molecules form per coulomb — so the collected hydrogen is always exactly twice the volume of oxygen (2:1).

What the animation shows

Both carbon electrodes are immersed in one beaker of acidified water, each under an inverted collection tube. H⁺ ions drift to the cathode and SO₄²⁻ ions to the anode; electrons run through the outer wire. Bubbles rise into the tubes and the H₂ column grows at twice the rate of the O₂ column, so the gas levels stay locked at 2:1. Turn the switch OFF and the current is zero — all bubbling stops.

Half-reactions

Quantities

Sources

Atkins, Physical Chemistry (Faraday's laws of electrolysis); NCERT Chemistry (electrolysis of acidified water; Hofmann voltammeter demo); CODATA 2018 (F = 96485.33 C/mol); ideal-gas molar volume 24.0 L/mol at 298 K, 1 atm (22.4 L/mol at STP). Time is a scaled simulation clock.